यदि (n\(A\cup B\)=74), (n(A-B)=28) और (n(B-A)=19) है, तो (n\(A\cap B\)) कितना होगा?
If (n\(A\cup B\)=74), (n(A-B)=28), and (n(B-A)=19), what is (n\(A\cap B\))?
Explanation opens after your attempt
C. (27)
Concept
The union has three separate parts, so (n\(A\cap B\)=74-28-19=27). In a Venn diagram, subtracting separate regions is easy.
Why this answer is correct
The correct answer is C. (27). The union has three separate parts, so (n\(A\cap B\)=74-28-19=27). In a Venn diagram, subtracting separate regions is easy.
Exam Tip
संघ के तीन अलग भाग होते हैं, इसलिए (n\(A\cap B\)=74-28-19=27)। वेन आरेख में अलग क्षेत्रों को सीधे घटाना आसान रहता है।
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