यदि (n\(A\cap B\)=48), (n\(A\cap C\)=41), (n\(B\cap C\)=39) और (n\(A\cap B\cap C\)=17) है, तो कम से कम दो समुच्चयों में आने वाले तत्व कितने हैं?

If (n\(A\cap B\)=48), (n\(A\cap C\)=41), (n\(B\cap C\)=39), and (n\(A\cap B\cap C\)=17), how many elements are in at least two sets?

Explanation opens after your attempt
Correct Answer

B. (94)

Step 1

Concept

At least two is ((48-17)+(41-17)+(39-17)+17=94). Find exactly two and then add the all-three part.

Step 2

Why this answer is correct

The correct answer is B. (94). At least two is ((48-17)+(41-17)+(39-17)+17=94). Find exactly two and then add the all-three part.

Step 3

Exam Tip

कम से कम दो (=(48-17)+(41-17)+(39-17)+17=94) है। ठीक दो निकालकर तीनों वाला भाग जोड़ें।

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यदि (n\(A\cap B\)=48), (n\(A\cap C\)=41), (n\(B\cap C\)=39) और (n\(A\cap B\cap C\)=17) है, तो कम से कम दो समुच्चयों में आने वाले तत्व कितने हैं? / If (n\(A\cap B\)=48), (n\(A\cap C\)=41), (n\(B\cap C\)=39), and (n\(A\cap B\cap C\)=17), how many elements are in at least two sets?

Correct Answer: B. (94). Explanation: कम से कम दो (=(48-17)+(41-17)+(39-17)+17=94) है। ठीक दो निकालकर तीनों वाला भाग जोड़ें। / At least two is ((48-17)+(41-17)+(39-17)+17=94). Find exactly two and then add the all-three part.

Which concept should I revise for this Mathematics MCQ?

At least two is ((48-17)+(41-17)+(39-17)+17=94). Find exactly two and then add the all-three part.

What exam hint can help solve this Mathematics question?

कम से कम दो (=(48-17)+(41-17)+(39-17)+17=94) है। ठीक दो निकालकर तीनों वाला भाग जोड़ें।