यदि (n\(A\cap B\)=42), (n\(A\cap C\)=36), (n\(B\cap C\)=34) और (n\(A\cap B\cap C\)=15) है, तो कम से कम दो समुच्चयों में आने वाले तत्व कितने हैं?
If (n\(A\cap B\)=42), (n\(A\cap C\)=36), (n\(B\cap C\)=34), and (n\(A\cap B\cap C\)=15), how many elements are in at least two sets?
Explanation opens after your attempt
A. (67)
Concept
At least two should be ((42-15)+(36-15)+(34-15)+15=82), so the correct value is (82). First find exactly two and then add the all-three part.
Why this answer is correct
The correct answer is A. (67). At least two should be ((42-15)+(36-15)+(34-15)+15=82), so the correct value is (82). First find exactly two and then add the all-three part.
Exam Tip
कम से कम दो (=(42-15)+(36-15)+(34-15)+15=82) होना चाहिए, इसलिए सही मान (82) है। पहले ठीक दो निकालें और फिर तीनों वाला भाग जोड़ें।
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