यदि (n(A-B)=4x+1), (n(B-A)=3x+6), (n\(A\cap B\)=2x+5) और (n\(A\cup B\)=120) है, तो (x) कितना है?
If (n(A-B)=4x+1), (n(B-A)=3x+6), (n\(A\cap B\)=2x+5) and (n\(A\cup B\)=120), then what is (x)?
Explanation opens after your attempt
A. (12)
Concept
The union is (4x+1+3x+6+2x+5=9x+12=120), so (x=12). The sum of disjoint Venn regions directly gives the union.
Why this answer is correct
The correct answer is A. (12). The union is (4x+1+3x+6+2x+5=9x+12=120), so (x=12). The sum of disjoint Venn regions directly gives the union.
Exam Tip
संघ (4x+1+3x+6+2x+5=9x+12=120), इसलिए (x=12) है। अलग वेन क्षेत्रों का योग सीधे संघ देता है।
Login to save your score, XP, coins and progress.
