यदि (n(A)=80), (n\(A\cap B\)=35), (n\(A\cap C\)=32) और (n\(A\cap B\cap C\)=14) है, तो केवल (A) में आने वाले तत्व कितने हैं?
If (n(A)=80), (n\(A\cap B\)=35), (n\(A\cap C\)=32), and (n\(A\cap B\cap C\)=14), how many elements are only in (A)?
Explanation opens after your attempt
C. (27)
Concept
Only (A=80-35-32+14=27). The central part is subtracted twice, so add it back once.
Why this answer is correct
The correct answer is C. (27). Only (A=80-35-32+14=27). The central part is subtracted twice, so add it back once.
Exam Tip
केवल (A=80-35-32+14=27) है। केंद्रीय भाग दो बार घटता है, इसलिए एक बार वापस जोड़ें।
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