यदि (n(A)=42), (n\(A\cap B\)=15), (n\(A\cap C\)=18) और (n\(A\cap B\cap C\)=7) है, तो केवल (A) कितने हैं?
If (n(A)=42), (n\(A\cap B\)=15), (n\(A\cap C\)=18), and (n\(A\cap B\cap C\)=7), how many are only in (A)?
Explanation opens after your attempt
A. (16)
Concept
Only (A=42-15-18+7=16). In three circles, adjustment of the central part is necessary.
Why this answer is correct
The correct answer is A. (16). Only (A=42-15-18+7=16). In three circles, adjustment of the central part is necessary.
Exam Tip
केवल (A=42-15-18+7=16)। तीन वृत्तों में केंद्रीय भाग का समायोजन जरूरी है।
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