यदि (n(A)=42), (n\(A\cap B\)=15), (n\(A\cap C\)=18) और (n\(A\cap B\cap C\)=7) है, तो केवल (A) कितने हैं?

If (n(A)=42), (n\(A\cap B\)=15), (n\(A\cap C\)=18), and (n\(A\cap B\cap C\)=7), how many are only in (A)?

Explanation opens after your attempt
Correct Answer

A. (16)

Step 1

Concept

Only (A=42-15-18+7=16). In three circles, adjustment of the central part is necessary.

Step 2

Why this answer is correct

The correct answer is A. (16). Only (A=42-15-18+7=16). In three circles, adjustment of the central part is necessary.

Step 3

Exam Tip

केवल (A=42-15-18+7=16)। तीन वृत्तों में केंद्रीय भाग का समायोजन जरूरी है।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=42), (n\(A\cap B\)=15), (n\(A\cap C\)=18) और (n\(A\cap B\cap C\)=7) है, तो केवल (A) कितने हैं? / If (n(A)=42), (n\(A\cap B\)=15), (n\(A\cap C\)=18), and (n\(A\cap B\cap C\)=7), how many are only in (A)?

Correct Answer: A. (16). Explanation: केवल (A=42-15-18+7=16)। तीन वृत्तों में केंद्रीय भाग का समायोजन जरूरी है। / Only (A=42-15-18+7=16). In three circles, adjustment of the central part is necessary.

Which concept should I revise for this Mathematics MCQ?

Only (A=42-15-18+7=16). In three circles, adjustment of the central part is necessary.

What exam hint can help solve this Mathematics question?

केवल (A=42-15-18+7=16)। तीन वृत्तों में केंद्रीय भाग का समायोजन जरूरी है।