यदि (n(A)=40), (n(B)=36), (n(C)=28), (n\(A\cap B\)=14), (n\(B\cap C\)=10), (n\(C\cap A\)=12) और (n\(A\cap B\cap C\)=5) है, तो (n(\(A\cup B\cup C\)-C)) कितना है?
If (n(A)=40), (n(B)=36), (n(C)=28), (n\(A\cap B\)=14), (n\(B\cap C\)=10), (n\(C\cap A\)=12), and (n\(A\cap B\cap C\)=5), then what is (n(\(A\cup B\cup C\)-C))?
Explanation opens after your attempt
A. (45)
Concept
First (n\(A\cup B\cup C\)=73), then removing (28) elements of (C) leaves (45). In such questions, find the complete union first.
Why this answer is correct
The correct answer is A. (45). First (n\(A\cup B\cup C\)=73), then removing (28) elements of (C) leaves (45). In such questions, find the complete union first.
Exam Tip
पहले (n\(A\cup B\cup C\)=73) मिलता है, फिर (C) के (28) तत्व हटाने पर (45) बचते हैं। ऐसे प्रश्न में पहले पूरा संघ निकालें।
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