यदि (n(A)=36), (n(B)=42) और \(A\cap B=\varnothing\) है, तो ठीक एक समुच्चय में कितने तत्व होंगे?
If (n(A)=36), (n(B)=42), and \(A\cap B=\varnothing\), how many elements are in exactly one set?
Explanation opens after your attempt
D. (78)
Concept
When sets are disjoint, every element belongs to exactly one set, so (36+42=78). The common part is zero.
Why this answer is correct
The correct answer is D. (78). When sets are disjoint, every element belongs to exactly one set, so (36+42=78). The common part is zero.
Exam Tip
असंबद्ध होने पर हर तत्व ठीक एक समुच्चय में आता है, इसलिए (36+42=78)। साझा भाग शून्य है।
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