यदि (n(A)=36), (n(B)=42) और \(A\cap B=\varnothing\) है, तो ठीक एक समुच्चय में कितने तत्व होंगे?

If (n(A)=36), (n(B)=42), and \(A\cap B=\varnothing\), how many elements are in exactly one set?

Explanation opens after your attempt
Correct Answer

D. (78)

Step 1

Concept

When sets are disjoint, every element belongs to exactly one set, so (36+42=78). The common part is zero.

Step 2

Why this answer is correct

The correct answer is D. (78). When sets are disjoint, every element belongs to exactly one set, so (36+42=78). The common part is zero.

Step 3

Exam Tip

असंबद्ध होने पर हर तत्व ठीक एक समुच्चय में आता है, इसलिए (36+42=78)। साझा भाग शून्य है।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=36), (n(B)=42) और \(A\cap B=\varnothing\) है, तो ठीक एक समुच्चय में कितने तत्व होंगे? / If (n(A)=36), (n(B)=42), and \(A\cap B=\varnothing\), how many elements are in exactly one set?

Correct Answer: D. (78). Explanation: असंबद्ध होने पर हर तत्व ठीक एक समुच्चय में आता है, इसलिए (36+42=78)। साझा भाग शून्य है। / When sets are disjoint, every element belongs to exactly one set, so (36+42=78). The common part is zero.

Which concept should I revise for this Mathematics MCQ?

When sets are disjoint, every element belongs to exactly one set, so (36+42=78). The common part is zero.

What exam hint can help solve this Mathematics question?

असंबद्ध होने पर हर तत्व ठीक एक समुच्चय में आता है, इसलिए (36+42=78)। साझा भाग शून्य है।