यदि (n(A)=30), (n(B)=24), (n\(A\setminus B\)=18) है, तो (n\(A\cup B\)) कितना है?
If (n(A)=30), (n(B)=24), and (n\(A\setminus B\)=18), then what is (n\(A\cup B\))?
Explanation opens after your attempt
Correct Answer
A. (42)
Concept
(n\(A\cap B\)=30-18=12). Thus (n\(A\cup B\)=30+24-12=42).
Why this answer is correct
The correct answer is A. (42). (n\(A\cap B\)=30-18=12). Thus (n\(A\cup B\)=30+24-12=42).
Exam Tip
(n\(A\cap B\)=30-18=12) है। अतः (n\(A\cup B\)=30+24-12=42)।
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