यदि (\frac{n!}{(n-2)!}=132) है तो (n) का मान क्या है?

If (\frac{n!}{(n-2)!}=132) then what is the value of (n)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

The equation becomes (n(n-1)=132). Since \(12\times11=132\), (n=12).

Step 2

Why this answer is correct

The correct answer is C. (12). The equation becomes (n(n-1)=132). Since \(12\times11=132\), (n=12).

Step 3

Exam Tip

समीकरण (n(n-1)=132) बनता है। \(12\times11=132\) इसलिए (n=12) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (\frac{n!}{(n-2)!}=132) है तो (n) का मान क्या है? / If (\frac{n!}{(n-2)!}=132) then what is the value of (n)?

Correct Answer: C. (12). Explanation: समीकरण (n(n-1)=132) बनता है। \(12\times11=132\) इसलिए (n=12) है। / The equation becomes (n(n-1)=132). Since \(12\times11=132\), (n=12).

Which concept should I revise for this Mathematics MCQ?

The equation becomes (n(n-1)=132). Since \(12\times11=132\), (n=12).

What exam hint can help solve this Mathematics question?

समीकरण (n(n-1)=132) बनता है। \(12\times11=132\) इसलिए (n=12) है।