Class 11 Mathematics Permutations and Combinations Derivations of formulas and their connections Expert Level 64

यदि \(\frac{{}^{n}C_{r+1}}{{}^{n}C_r}=\frac{2}{3}\), तो (n), (r) के बीच कौन-सा relation बनेगा?

If \(\frac{{}^{n}C_{r+1}}{{}^{n}C_r}=\frac{2}{3}\), what relation is formed between (n) and (r)?

Explanation opens after your attempt
Correct Answer

A. (3n-5r=2)

Step 1

Concept

The ratio \(\frac{n-r}{r+1}=\frac{2}{3}\) gives (3n-3r=2r+2). In exams cross-multiply consecutive combination ratios.

Step 2

Why this answer is correct

The correct answer is A. (3n-5r=2). The ratio \(\frac{n-r}{r+1}=\frac{2}{3}\) gives (3n-3r=2r+2). In exams cross-multiply consecutive combination ratios.

Step 3

Exam Tip

Ratio \(\frac{n-r}{r+1}=\frac{2}{3}\) से (3n-3r=2r+2) मिलता है। परीक्षा में consecutive combination ratios को cross multiply करें।

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यदि \(\frac{{}^{n}C_{r+1}}{{}^{n}C_r}=\frac{2}{3}\), तो (n), (r) के बीच कौन-सा relation बनेगा? / If \(\frac{{}^{n}C_{r+1}}{{}^{n}C_r}=\frac{2}{3}\), what relation is formed between (n) and (r)?

Correct Answer: A. (3n-5r=2). Explanation: Ratio \(\frac{n-r}{r+1}=\frac{2}{3}\) से (3n-3r=2r+2) मिलता है। परीक्षा में consecutive combination ratios को cross multiply करें। / The ratio \(\frac{n-r}{r+1}=\frac{2}{3}\) gives (3n-3r=2r+2). In exams cross-multiply consecutive combination ratios.

Which concept should I revise for this Mathematics MCQ?

The ratio \(\frac{n-r}{r+1}=\frac{2}{3}\) gives (3n-3r=2r+2). In exams cross-multiply consecutive combination ratios.

What exam hint can help solve this Mathematics question?

Ratio \(\frac{n-r}{r+1}=\frac{2}{3}\) से (3n-3r=2r+2) मिलता है। परीक्षा में consecutive combination ratios को cross multiply करें।