यदि ( \frac{(n+5)!}{(n+3)!}=132 ), तो (n) का मान क्या है?
If ( \frac{(n+5)!}{(n+3)!}=132 ), what is the value of (n)?
Explanation opens after your attempt
B. (7)
Concept
((n+5)(n+4)=132) and \(12\cdot11=132\), so (n=7). Find (n) from consecutive factors.
Why this answer is correct
The correct answer is B. (7). ((n+5)(n+4)=132) and \(12\cdot11=132\), so (n=7). Find (n) from consecutive factors.
Exam Tip
((n+5)(n+4)=132) और \(12\cdot11=132\), इसलिए (n=7) है। लगातार गुणकों से (n) निकालें।
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