यदि ( \frac{(n+5)!}{(n+2)!}-\frac{(n+4)!}{(n+1)!}=396 ), तो (n) का मान क्या है?
If ( \frac{(n+5)!}{(n+2)!}-\frac{(n+4)!}{(n+1)!}=396 ), what is the value of (n)?
Explanation opens after your attempt
B. (8)
Concept
The simplified form is (3(n+4)(n+3)). Since \(3\cdot12\cdot11=396\), (n=8).
Why this answer is correct
The correct answer is B. (8). The simplified form is (3(n+4)(n+3)). Since \(3\cdot12\cdot11=396\), (n=8).
Exam Tip
सरल रूप (3(n+4)(n+3)) है। \(3\cdot12\cdot11=396\), इसलिए (n=8)।
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