यदि ( \frac{(n+4)!+(n+3)!}{(n+2)!}=120 ), तो (n) का मान क्या है?

If ( \frac{(n+4)!+(n+3)!}{(n+2)!}=120 ), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

The simplified form is ((n+3)(n+5)), so ((n+3)(n+5)=120). Since \(10\cdot12=120\), (n=7).

Step 2

Why this answer is correct

The correct answer is B. (7). The simplified form is ((n+3)(n+5)), so ((n+3)(n+5)=120). Since \(10\cdot12=120\), (n=7).

Step 3

Exam Tip

सरल रूप ((n+3)(n+5)) है, इसलिए ((n+3)(n+5)=120)। \(10\cdot12=120\), इसलिए (n=7)।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(n+4)!+(n+3)!}{(n+2)!}=120 ), तो (n) का मान क्या है? / If ( \frac{(n+4)!+(n+3)!}{(n+2)!}=120 ), what is the value of (n)?

Correct Answer: B. (7). Explanation: सरल रूप ((n+3)(n+5)) है, इसलिए ((n+3)(n+5)=120)। \(10\cdot12=120\), इसलिए (n=7)। / The simplified form is ((n+3)(n+5)), so ((n+3)(n+5)=120). Since \(10\cdot12=120\), (n=7).

Which concept should I revise for this Mathematics MCQ?

The simplified form is ((n+3)(n+5)), so ((n+3)(n+5)=120). Since \(10\cdot12=120\), (n=7).

What exam hint can help solve this Mathematics question?

सरल रूप ((n+3)(n+5)) है, इसलिए ((n+3)(n+5)=120)। \(10\cdot12=120\), इसलिए (n=7)।