यदि ( \frac{(n+4)!+(n+3)!}{(n+2)!}=120 ), तो (n) का मान क्या है?
If ( \frac{(n+4)!+(n+3)!}{(n+2)!}=120 ), what is the value of (n)?
Explanation opens after your attempt
B. (7)
Concept
The simplified form is ((n+3)(n+5)), so ((n+3)(n+5)=120). Since \(10\cdot12=120\), (n=7).
Why this answer is correct
The correct answer is B. (7). The simplified form is ((n+3)(n+5)), so ((n+3)(n+5)=120). Since \(10\cdot12=120\), (n=7).
Exam Tip
सरल रूप ((n+3)(n+5)) है, इसलिए ((n+3)(n+5)=120)। \(10\cdot12=120\), इसलिए (n=7)।
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