Mathematics Answer, Explanation and Revision Hints
यदि ( \frac{(n+4)!}{(n+2)!}-\frac{(n+3)!}{(n+1)!}=24 ), तो (n) का मान क्या है? / If ( \frac{(n+4)!}{(n+2)!}-\frac{(n+3)!}{(n+1)!}=24 ), what is the value of (n)?
Correct Answer: C. (9). Explanation: सरल रूप (2(n+3)) है। इसलिए (2(n+3)=24) और (n=9)। / The simplified form is (2(n+3)). Thus (2(n+3)=24) and (n=9).
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