यदि ( \frac{(n+4)!}{(n+2)!}-\frac{(n+3)!}{(n+1)!}=24 ), तो (n) का मान क्या है?
If ( \frac{(n+4)!}{(n+2)!}-\frac{(n+3)!}{(n+1)!}=24 ), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
C. (9)
Concept
The simplified form is (2(n+3)). Thus (2(n+3)=24) and (n=9).
Why this answer is correct
The correct answer is C. (9). The simplified form is (2(n+3)). Thus (2(n+3)=24) and (n=9).
Exam Tip
सरल रूप (2(n+3)) है। इसलिए (2(n+3)=24) और (n=9)।
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