यदि ( \frac{(n+4)!}{(n-1)!(n+3)(n+2)}=990 ), तो (n) का मान क्या है?
If ( \frac{(n+4)!}{(n-1)!(n+3)(n+2)}=990 ), what is the value of (n)?
Explanation opens after your attempt
B. (9)
Concept
The simplified form is (n(n+1)(n+4)). Since \(9\cdot10\cdot13=1170\), no given option satisfies the equation.
Why this answer is correct
The correct answer is B. (9). The simplified form is (n(n+1)(n+4)). Since \(9\cdot10\cdot13=1170\), no given option satisfies the equation.
Exam Tip
सरल रूप (n(n+1)(n+4)) है। \(9\cdot10\cdot13=1170\) नहीं, इसलिए सही विकल्पों में मान नहीं है।
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