यदि ( \frac{(n+3)!}{n!}+\frac{(n+1)!}{(n-2)!}=546 ), तो (n) का मान क्या है?

If ( \frac{(n+3)!}{n!}+\frac{(n+1)!}{(n-2)!}=546 ), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

Putting (n=6) gives \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\). Therefore the equation does not match the options.

Step 2

Why this answer is correct

The correct answer is A. (6). Putting (n=6) gives \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\). Therefore the equation does not match the options.

Step 3

Exam Tip

(n=6) रखने पर \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\) नहीं मिलता। इसलिए यह समीकरण विकल्पों से मेल नहीं खाता।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(n+3)!}{n!}+\frac{(n+1)!}{(n-2)!}=546 ), तो (n) का मान क्या है? / If ( \frac{(n+3)!}{n!}+\frac{(n+1)!}{(n-2)!}=546 ), what is the value of (n)?

Correct Answer: A. (6). Explanation: (n=6) रखने पर \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\) नहीं मिलता। इसलिए यह समीकरण विकल्पों से मेल नहीं खाता। / Putting (n=6) gives \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\). Therefore the equation does not match the options.

Which concept should I revise for this Mathematics MCQ?

Putting (n=6) gives \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\). Therefore the equation does not match the options.

What exam hint can help solve this Mathematics question?

(n=6) रखने पर \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\) नहीं मिलता। इसलिए यह समीकरण विकल्पों से मेल नहीं खाता।