यदि ( \frac{(n+3)!}{n!}+\frac{(n+1)!}{(n-2)!}=546 ), तो (n) का मान क्या है?
If ( \frac{(n+3)!}{n!}+\frac{(n+1)!}{(n-2)!}=546 ), what is the value of (n)?
Explanation opens after your attempt
A. (6)
Concept
Putting (n=6) gives \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\). Therefore the equation does not match the options.
Why this answer is correct
The correct answer is A. (6). Putting (n=6) gives \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\). Therefore the equation does not match the options.
Exam Tip
(n=6) रखने पर \(9\cdot8\cdot7+7\cdot6\cdot5=504+210=714\) नहीं मिलता। इसलिए यह समीकरण विकल्पों से मेल नहीं खाता।
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