यदि ( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!}=114 ), तो (n) का मान क्या है?

If ( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!}=114 ), what is the value of (n)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (7)

Explanation

Simple Explanation

सरल रूप \(2n^2+2n+2\) है। (n=7) रखने पर (98+14+2=114) मिलता है। / The simplified form is \(2n^2+2n+2\). Putting (n=7) gives (98+14+2=114).

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!}=114 ), तो (n) का मान क्या है? / If ( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!}=114 ), what is the value of (n)?

Correct Answer: B. (7). Explanation: सरल रूप \(2n^2+2n+2\) है। (n=7) रखने पर (98+14+2=114) मिलता है। / The simplified form is \(2n^2+2n+2\). Putting (n=7) gives (98+14+2=114).