यदि ( \frac{(n+2)!}{(n-2)!}=1680 ), तो (n) का मान क्या है?

If ( \frac{(n+2)!}{(n-2)!}=1680 ), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

D. (6)

Step 1

Concept

It is ((n+2)(n+1)n(n-1)=1680). Since \(8\cdot7\cdot6\cdot5=1680\), (n=6).

Step 2

Why this answer is correct

The correct answer is D. (6). It is ((n+2)(n+1)n(n-1)=1680). Since \(8\cdot7\cdot6\cdot5=1680\), (n=6).

Step 3

Exam Tip

यह ((n+2)(n+1)n(n-1)=1680) है। \(8\cdot7\cdot6\cdot5=1680\), इसलिए (n=6)।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(n+2)!}{(n-2)!}=1680 ), तो (n) का मान क्या है? / If ( \frac{(n+2)!}{(n-2)!}=1680 ), what is the value of (n)?

Correct Answer: D. (6). Explanation: यह ((n+2)(n+1)n(n-1)=1680) है। \(8\cdot7\cdot6\cdot5=1680\), इसलिए (n=6)। / It is ((n+2)(n+1)n(n-1)=1680). Since \(8\cdot7\cdot6\cdot5=1680\), (n=6).

Which concept should I revise for this Mathematics MCQ?

It is ((n+2)(n+1)n(n-1)=1680). Since \(8\cdot7\cdot6\cdot5=1680\), (n=6).

What exam hint can help solve this Mathematics question?

यह ((n+2)(n+1)n(n-1)=1680) है। \(8\cdot7\cdot6\cdot5=1680\), इसलिए (n=6)।