यदि ( \frac{(n+2)!}{(n-2)!}=1680 ), तो (n) का मान क्या है?
If ( \frac{(n+2)!}{(n-2)!}=1680 ), what is the value of (n)?
Explanation opens after your attempt
D. (6)
Concept
It is ((n+2)(n+1)n(n-1)=1680). Since \(8\cdot7\cdot6\cdot5=1680\), (n=6).
Why this answer is correct
The correct answer is D. (6). It is ((n+2)(n+1)n(n-1)=1680). Since \(8\cdot7\cdot6\cdot5=1680\), (n=6).
Exam Tip
यह ((n+2)(n+1)n(n-1)=1680) है। \(8\cdot7\cdot6\cdot5=1680\), इसलिए (n=6)।
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