यदि ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{13}{14} ), तो (n) का मान क्या है?
If ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{13}{14} ), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
B. (13)
Concept
The simplified form is \( \frac{n}{n+1} \). Since \( \frac{n}{n+1}=\frac{13}{14} \), (n=13).
Why this answer is correct
The correct answer is B. (13). The simplified form is \( \frac{n}{n+1} \). Since \( \frac{n}{n+1}=\frac{13}{14} \), (n=13).
Exam Tip
सरल रूप \( \frac{n}{n+1} \) है। \( \frac{n}{n+1}=\frac{13}{14} \), इसलिए (n=13)।
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