यदि ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{11}{12} ), तो (n) का मान क्या है?

If ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{11}{12} ), what is the value of (n)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (11)

Explanation

Simple Explanation

सरल रूप \( \frac{n}{n+1} \) है। \( \frac{n}{n+1}=\frac{11}{12} \) से (n=11) मिलता है। / The simplified form is \( \frac{n}{n+1} \). From \( \frac{n}{n+1}=\frac{11}{12} \), we get (n=11).

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{11}{12} ), तो (n) का मान क्या है? / If ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{11}{12} ), what is the value of (n)?

Correct Answer: B. (11). Explanation: सरल रूप \( \frac{n}{n+1} \) है। \( \frac{n}{n+1}=\frac{11}{12} \) से (n=11) मिलता है। / The simplified form is \( \frac{n}{n+1} \). From \( \frac{n}{n+1}=\frac{11}{12} \), we get (n=11).