यदि ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{11}{12} ), तो (n) का मान क्या है?
If ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{11}{12} ), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
B. (11)
Concept
The simplified form is \( \frac{n}{n+1} \). From \( \frac{n}{n+1}=\frac{11}{12} \), we get (n=11).
Why this answer is correct
The correct answer is B. (11). The simplified form is \( \frac{n}{n+1} \). From \( \frac{n}{n+1}=\frac{11}{12} \), we get (n=11).
Exam Tip
सरल रूप \( \frac{n}{n+1} \) है। \( \frac{n}{n+1}=\frac{11}{12} \) से (n=11) मिलता है।
Login to save your score, XP, coins and progress.