यदि \( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=24 \), तो \(n\) का मान क्या है?
If \( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=24 \), what is the value of \(n\)?
Explanation opens after your attempt
Correct Answer
C. (12)
Concept
The simplified form is (2n), so \(2n=24\). Hence \(n=12\).
Why this answer is correct
The correct answer is C. (12). The simplified form is (2n), so \(2n=24\). Hence \(n=12\).
Exam Tip
सरल रूप (2n) है, इसलिए \(2n=24\)। अतः \(n=12\)।
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