यदि ( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=18 ), तो (n) का मान क्या है?

If ( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=18 ), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

The simplified form is (2n), so (2n=18). Hence (n=9).

Step 2

Why this answer is correct

The correct answer is B. (9). The simplified form is (2n), so (2n=18). Hence (n=9).

Step 3

Exam Tip

सरल रूप (2n) है, इसलिए (2n=18)। अतः (n=9)।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=18 ), तो (n) का मान क्या है? / If ( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=18 ), what is the value of (n)?

Correct Answer: B. (9). Explanation: सरल रूप (2n) है, इसलिए (2n=18)। अतः (n=9)। / The simplified form is (2n), so (2n=18). Hence (n=9).

Which concept should I revise for this Mathematics MCQ?

The simplified form is (2n), so (2n=18). Hence (n=9).

What exam hint can help solve this Mathematics question?

सरल रूप (2n) है, इसलिए (2n=18)। अतः (n=9)।