यदि ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}}=\frac{5}{2} ), तो (n) का मान क्या है?

If ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}}=\frac{5}{2} ), what is the value of (n)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (4)

Explanation

Simple Explanation

सरल रूप \( \frac{n+3}{n-2} \) है। \( \frac{n+3}{n-2}=\frac{5}{2} \) से (n=4) मिलता है। / The simplified form is \( \frac{n+3}{n-2} \). From \( \frac{n+3}{n-2}=\frac{5}{2} \), we get (n=4).

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}}=\frac{5}{2} ), तो (n) का मान क्या है? / If ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}}=\frac{5}{2} ), what is the value of (n)?

Correct Answer: B. (4). Explanation: सरल रूप \( \frac{n+3}{n-2} \) है। \( \frac{n+3}{n-2}=\frac{5}{2} \) से (n=4) मिलता है। / The simplified form is \( \frac{n+3}{n-2} \). From \( \frac{n+3}{n-2}=\frac{5}{2} \), we get (n=4).