यदि ( \frac{\frac{(n+2)!}{(n-2)!}}{\frac{(n+1)!}{(n-3)!}}=2 ), तो (n) का मान क्या है?

If ( \frac{\frac{(n+2)!}{(n-2)!}}{\frac{(n+1)!}{(n-3)!}}=2 ), what is the value of (n)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (6)

Explanation

Simple Explanation

सरल रूप \( \frac{n+2}{n-2} \) है। \( \frac{n+2}{n-2}=2 \) से (n=6) मिलता है। / The simplified form is \( \frac{n+2}{n-2} \). From \( \frac{n+2}{n-2}=2 \), we get (n=6).

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{\frac{(n+2)!}{(n-2)!}}{\frac{(n+1)!}{(n-3)!}}=2 ), तो (n) का मान क्या है? / If ( \frac{\frac{(n+2)!}{(n-2)!}}{\frac{(n+1)!}{(n-3)!}}=2 ), what is the value of (n)?

Correct Answer: C. (6). Explanation: सरल रूप \( \frac{n+2}{n-2} \) है। \( \frac{n+2}{n-2}=2 \) से (n=6) मिलता है। / The simplified form is \( \frac{n+2}{n-2} \). From \( \frac{n+2}{n-2}=2 \), we get (n=6).