यदि ( \frac{(4n+1)!}{(4n-1)!}=420 ), तो (n) का मान क्या है?
If ( \frac{(4n+1)!}{(4n-1)!}=420 ), what is the value of (n)?
Explanation opens after your attempt
B. (5)
Concept
It is ((4n+1)(4n)=420). Since \(21\cdot20=420\), (4n=20) and (n=5).
Why this answer is correct
The correct answer is B. (5). It is ((4n+1)(4n)=420). Since \(21\cdot20=420\), (4n=20) and (n=5).
Exam Tip
यह ((4n+1)(4n)=420) है। \(21\cdot20=420\), इसलिए (4n=20) और (n=5)।
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