यदि ( \frac{(3n)!}{(3n-2)!}=132 ), तो (n) का मान क्या है?
If ( \frac{(3n)!}{(3n-2)!}=132 ), what is the value of (n)?
Explanation opens after your attempt
D. (4)
Concept
It is (3n(3n-1)=132), and \(12\cdot11=132\), so (3n=12). Hence (n=4).
Why this answer is correct
The correct answer is D. (4). It is (3n(3n-1)=132), and \(12\cdot11=132\), so (3n=12). Hence (n=4).
Exam Tip
यह (3n(3n-1)=132) है और \(12\cdot11=132\), इसलिए (3n=12)। अतः (n=4)।
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