यदि ( \frac{(3n)!}{(3n-2)!}=132 ), तो (n) का मान क्या है?

If ( \frac{(3n)!}{(3n-2)!}=132 ), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

D. (4)

Step 1

Concept

It is (3n(3n-1)=132), and \(12\cdot11=132\), so (3n=12). Hence (n=4).

Step 2

Why this answer is correct

The correct answer is D. (4). It is (3n(3n-1)=132), and \(12\cdot11=132\), so (3n=12). Hence (n=4).

Step 3

Exam Tip

यह (3n(3n-1)=132) है और \(12\cdot11=132\), इसलिए (3n=12)। अतः (n=4)।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(3n)!}{(3n-2)!}=132 ), तो (n) का मान क्या है? / If ( \frac{(3n)!}{(3n-2)!}=132 ), what is the value of (n)?

Correct Answer: D. (4). Explanation: यह (3n(3n-1)=132) है और \(12\cdot11=132\), इसलिए (3n=12)। अतः (n=4)। / It is (3n(3n-1)=132), and \(12\cdot11=132\), so (3n=12). Hence (n=4).

Which concept should I revise for this Mathematics MCQ?

It is (3n(3n-1)=132), and \(12\cdot11=132\), so (3n=12). Hence (n=4).

What exam hint can help solve this Mathematics question?

यह (3n(3n-1)=132) है और \(12\cdot11=132\), इसलिए (3n=12)। अतः (n=4)।