यदि ( \frac{(3n+2)!}{(3n)!}=182 ), तो (n) का मान क्या है?
If ( \frac{(3n+2)!}{(3n)!}=182 ), what is the value of (n)?
Explanation opens after your attempt
B. (4)
Concept
It is ((3n+2)(3n+1)=182), and \(14\cdot13=182\). Thus (3n+2=14) and (n=4).
Why this answer is correct
The correct answer is B. (4). It is ((3n+2)(3n+1)=182), and \(14\cdot13=182\). Thus (3n+2=14) and (n=4).
Exam Tip
यह ((3n+2)(3n+1)=182) है और \(14\cdot13=182\)। इसलिए (3n+2=14) और (n=4)।
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