यदि ( \frac{(3n+2)!}{(3n)!}=182 ), तो (n) का मान क्या है?

If ( \frac{(3n+2)!}{(3n)!}=182 ), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

It is ((3n+2)(3n+1)=182), and \(14\cdot13=182\). Thus (3n+2=14) and (n=4).

Step 2

Why this answer is correct

The correct answer is B. (4). It is ((3n+2)(3n+1)=182), and \(14\cdot13=182\). Thus (3n+2=14) and (n=4).

Step 3

Exam Tip

यह ((3n+2)(3n+1)=182) है और \(14\cdot13=182\)। इसलिए (3n+2=14) और (n=4)।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(3n+2)!}{(3n)!}=182 ), तो (n) का मान क्या है? / If ( \frac{(3n+2)!}{(3n)!}=182 ), what is the value of (n)?

Correct Answer: B. (4). Explanation: यह ((3n+2)(3n+1)=182) है और \(14\cdot13=182\)। इसलिए (3n+2=14) और (n=4)। / It is ((3n+2)(3n+1)=182), and \(14\cdot13=182\). Thus (3n+2=14) and (n=4).

Which concept should I revise for this Mathematics MCQ?

It is ((3n+2)(3n+1)=182), and \(14\cdot13=182\). Thus (3n+2=14) and (n=4).

What exam hint can help solve this Mathematics question?

यह ((3n+2)(3n+1)=182) है और \(14\cdot13=182\)। इसलिए (3n+2=14) और (n=4)।