यदि ( \frac{(2n+3)!}{(2n-1)!}=17160 ), तो (n) का मान क्या है?
If ( \frac{(2n+3)!}{(2n-1)!}=17160 ), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
B. (5)
Concept
It is ((2n+3)(2n+2)(2n+1)(2n)=17160). Since \(13\cdot12\cdot11\cdot10=17160\), (n=5).
Why this answer is correct
The correct answer is B. (5). It is ((2n+3)(2n+2)(2n+1)(2n)=17160). Since \(13\cdot12\cdot11\cdot10=17160\), (n=5).
Exam Tip
यह ((2n+3)(2n+2)(2n+1)(2n)=17160) है। \(13\cdot12\cdot11\cdot10=17160\), इसलिए (n=5)।
Login to save your score, XP, coins and progress.