यदि ( \frac{(2n+1)!}{(2n-1)!}=306 ), तो (n) का मान क्या है?

If ( \frac{(2n+1)!}{(2n-1)!}=306 ), what is the value of (n)?

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Correct Answer

B. (8)

Step 1

Concept

It is ((2n+1)(2n)=306), and no integer (n) satisfies it. Check whether the matched consecutive factors fit the form.

Step 2

Why this answer is correct

The correct answer is B. (8). It is ((2n+1)(2n)=306), and no integer (n) satisfies it. Check whether the matched consecutive factors fit the form.

Step 3

Exam Tip

यह ((2n+1)(2n)=306) है और \(17\cdot16=272\) नहीं; सही समीकरण के लिए कोई पूर्णांक (n) नहीं मिलेगा।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(2n+1)!}{(2n-1)!}=306 ), तो (n) का मान क्या है? / If ( \frac{(2n+1)!}{(2n-1)!}=306 ), what is the value of (n)?

Correct Answer: B. (8). Explanation: यह ((2n+1)(2n)=306) है और \(17\cdot16=272\) नहीं; सही समीकरण के लिए कोई पूर्णांक (n) नहीं मिलेगा। / It is ((2n+1)(2n)=306), and no integer (n) satisfies it. Check whether the matched consecutive factors fit the form.

Which concept should I revise for this Mathematics MCQ?

It is ((2n+1)(2n)=306), and no integer (n) satisfies it. Check whether the matched consecutive factors fit the form.

What exam hint can help solve this Mathematics question?

यह ((2n+1)(2n)=306) है और \(17\cdot16=272\) नहीं; सही समीकरण के लिए कोई पूर्णांक (n) नहीं मिलेगा।