यदि ( \frac{(2n+1)!}{(2n-1)!}=306 ), तो (n) का मान क्या है?
If ( \frac{(2n+1)!}{(2n-1)!}=306 ), what is the value of (n)?
Explanation opens after your attempt
B. (8)
Concept
It is ((2n+1)(2n)=306), and no integer (n) satisfies it. Check whether the matched consecutive factors fit the form.
Why this answer is correct
The correct answer is B. (8). It is ((2n+1)(2n)=306), and no integer (n) satisfies it. Check whether the matched consecutive factors fit the form.
Exam Tip
यह ((2n+1)(2n)=306) है और \(17\cdot16=272\) नहीं; सही समीकरण के लिए कोई पूर्णांक (n) नहीं मिलेगा।
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