यदि (f(x)=x+\frac{3}{x}) और (g(x)=x-\frac{3}{x}) हैं, तो ((fg)(x)) क्या है?

If (f(x)=x+\frac{3}{x}) and (g(x)=x-\frac{3}{x}), what is ((fg)(x))?

Explanation opens after your attempt
Correct Answer

C. \(x^2-\frac{9}{x^2}\), \(x\ne 0\)

Step 1

Concept

((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2}). Use ((a+b)(a-b)=a-2-b-2) here.

Step 2

Why this answer is correct

The correct answer is C. \(x^2-\frac{9}{x^2}\), \(x\ne 0\). ((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2}). Use ((a+b)(a-b)=a-2-b-2) here.

Step 3

Exam Tip

((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2})। यहां ((a+b)(a-b)=a-2-b-2) लगती है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x+\frac{3}{x}) और (g(x)=x-\frac{3}{x}) हैं, तो ((fg)(x)) क्या है? / If (f(x)=x+\frac{3}{x}) and (g(x)=x-\frac{3}{x}), what is ((fg)(x))?

Correct Answer: C. \(x^2-\frac{9}{x^2}\), \(x\ne 0\). Explanation: ((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2})। यहां ((a+b)(a-b)=a-2-b-2) लगती है। / ((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2}). Use ((a+b)(a-b)=a-2-b-2) here.

Which concept should I revise for this Mathematics MCQ?

((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2}). Use ((a+b)(a-b)=a-2-b-2) here.

What exam hint can help solve this Mathematics question?

((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2})। यहां ((a+b)(a-b)=a-2-b-2) लगती है।