यदि (f(x)=x+\frac{3}{x}) और (g(x)=x-\frac{3}{x}) हैं, तो ((fg)(x)) क्या है?
If (f(x)=x+\frac{3}{x}) and (g(x)=x-\frac{3}{x}), what is ((fg)(x))?
Explanation opens after your attempt
C. \(x^2-\frac{9}{x^2}\), \(x\ne 0\)
Concept
((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2}). Use ((a+b)(a-b)=a-2-b-2) here.
Why this answer is correct
The correct answer is C. \(x^2-\frac{9}{x^2}\), \(x\ne 0\). ((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2}). Use ((a+b)(a-b)=a-2-b-2) here.
Exam Tip
((fg)(x)=\left\(x+\frac{3}{x}\right\)\left\(x-\frac{3}{x}\right\)=x-2-\frac{9}{x-2})। यहां ((a+b)(a-b)=a-2-b-2) लगती है।
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