यदि (f(x)=x-2+x) और (g(x)=x) हैं, तो \(x \neq 0\) के लिए (\left\(\frac{f}{g}\right\)(x)) क्या है?

If (f(x)=x-2+x) and (g(x)=x), what is (\left\(\frac{f}{g}\right\)(x)) for \(x \neq 0\)?

Explanation opens after your attempt
Correct Answer

A. (x+1)

Step 1

Concept

(\frac{x-2+x}{x}=\frac{x(x+1)}{x}=x+1), where \(x \neq 0\). Do not forget the restriction while cancelling a common factor.

Step 2

Why this answer is correct

The correct answer is A. (x+1). (\frac{x-2+x}{x}=\frac{x(x+1)}{x}=x+1), where \(x \neq 0\). Do not forget the restriction while cancelling a common factor.

Step 3

Exam Tip

(\frac{x-2+x}{x}=\frac{x(x+1)}{x}=x+1), जहाँ \(x \neq 0\)। साझा गुणनखंड काटते समय प्रतिबंध न भूलें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2+x) और (g(x)=x) हैं, तो \(x \neq 0\) के लिए (\left\(\frac{f}{g}\right\)(x)) क्या है? / If (f(x)=x-2+x) and (g(x)=x), what is (\left\(\frac{f}{g}\right\)(x)) for \(x \neq 0\)?

Correct Answer: A. (x+1). Explanation: (\frac{x-2+x}{x}=\frac{x(x+1)}{x}=x+1), जहाँ \(x \neq 0\)। साझा गुणनखंड काटते समय प्रतिबंध न भूलें। / (\frac{x-2+x}{x}=\frac{x(x+1)}{x}=x+1), where \(x \neq 0\). Do not forget the restriction while cancelling a common factor.

Which concept should I revise for this Mathematics MCQ?

(\frac{x-2+x}{x}=\frac{x(x+1)}{x}=x+1), where \(x \neq 0\). Do not forget the restriction while cancelling a common factor.

What exam hint can help solve this Mathematics question?

(\frac{x-2+x}{x}=\frac{x(x+1)}{x}=x+1), जहाँ \(x \neq 0\)। साझा गुणनखंड काटते समय प्रतिबंध न भूलें।