\(\frac{g}{f}=\frac{x^2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2\), पर \(x\ne -2\)। रद्द किए गए गुणनखंड का शून्य भी हटाएँ। / \(\frac{g}{f}=\frac{x^2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2\), but \(x\ne -2\). Exclude the zero of the cancelled factor too.
Mathematics Answer, Explanation and Revision Hints
यदि \(f(x)=x+2\) और \(g(x)=x^2-4\) हैं तो \(\left(\frac{g}{f}\right)(x)\) का सरल रूप क्या है? / If \(f(x)=x+2\) and \(g(x)=x^2-4\) then what is the simplified form of \(\left(\frac{g}{f}\right)(x)\)?
Correct Answer: A. (x-2), \(x\ne -2\). Explanation: \(\frac{g}{f}=\frac{x^2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2\), पर \(x\ne -2\)। रद्द किए गए गुणनखंड का शून्य भी हटाएँ। / \(\frac{g}{f}=\frac{x^2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2\), but \(x\ne -2\). Exclude the zero of the cancelled factor too.
Login to view answers
Use Google login or mobile OTP. Admin can block users and control login providers.
Privacy preferences
Hum essential cookies/session ka use login, class selection aur security ke liye karte hain. Analytics, marketing aur personalized ads optional hain.
