यदि (f(x)=x-2) और (g(x)=\sqrt{x}) हैं, तो ((f+g)(x)) का प्रांत क्या है?

If (f(x)=x-2) and (g(x)=\sqrt{x}), what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(x \geq 0\)

Step 1

Concept

\(x^2\) is defined for all real (x), but \(\sqrt{x}\) needs \(x \geq 0\). The domain of the sum is the intersection.

Step 2

Why this answer is correct

The correct answer is A. \(x \geq 0\). \(x^2\) is defined for all real (x), but \(\sqrt{x}\) needs \(x \geq 0\). The domain of the sum is the intersection.

Step 3

Exam Tip

\(x^2\) सभी वास्तविक (x) के लिए परिभाषित है, लेकिन \(\sqrt{x}\) के लिए \(x \geq 0\) चाहिए। योग का प्रांत प्रतिच्छेद है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2) और (g(x)=\sqrt{x}) हैं, तो ((f+g)(x)) का प्रांत क्या है? / If (f(x)=x-2) and (g(x)=\sqrt{x}), what is the domain of ((f+g)(x))?

Correct Answer: A. \(x \geq 0\). Explanation: \(x^2\) सभी वास्तविक (x) के लिए परिभाषित है, लेकिन \(\sqrt{x}\) के लिए \(x \geq 0\) चाहिए। योग का प्रांत प्रतिच्छेद है। / \(x^2\) is defined for all real (x), but \(\sqrt{x}\) needs \(x \geq 0\). The domain of the sum is the intersection.

Which concept should I revise for this Mathematics MCQ?

\(x^2\) is defined for all real (x), but \(\sqrt{x}\) needs \(x \geq 0\). The domain of the sum is the intersection.

What exam hint can help solve this Mathematics question?

\(x^2\) सभी वास्तविक (x) के लिए परिभाषित है, लेकिन \(\sqrt{x}\) के लिए \(x \geq 0\) चाहिए। योग का प्रांत प्रतिच्छेद है।