यदि (f(x)=x-2-9) और codomain \(\mathbb{R}\) है, तो वास्तविक डोमेन \(\mathbb{R}\) पर रेंज क्या है?

If (f(x)=x-2-9) and the codomain is \(\mathbb{R}\), what is the range on real domain \(\mathbb{R}\)?

Explanation opens after your attempt
Correct Answer

A. \([-9,\infty\))

Step 1

Concept

Since \(x^2\ge 0\), \(x^2-9\ge -9\). In exams keep the difference between codomain and actual range clear.

Step 2

Why this answer is correct

The correct answer is A. \([-9,\infty\)). Since \(x^2\ge 0\), \(x^2-9\ge -9\). In exams keep the difference between codomain and actual range clear.

Step 3

Exam Tip

क्योंकि \(x^2\ge 0\), इसलिए \(x^2-9\ge -9\)। परीक्षा में codomain और actual range में फर्क रखें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-9) और codomain \(\mathbb{R}\) है, तो वास्तविक डोमेन \(\mathbb{R}\) पर रेंज क्या है? / If (f(x)=x-2-9) and the codomain is \(\mathbb{R}\), what is the range on real domain \(\mathbb{R}\)?

Correct Answer: A. \([-9,\infty\)). Explanation: क्योंकि \(x^2\ge 0\), इसलिए \(x^2-9\ge -9\)। परीक्षा में codomain और actual range में फर्क रखें। / Since \(x^2\ge 0\), \(x^2-9\ge -9\). In exams keep the difference between codomain and actual range clear.

Which concept should I revise for this Mathematics MCQ?

Since \(x^2\ge 0\), \(x^2-9\ge -9\). In exams keep the difference between codomain and actual range clear.

What exam hint can help solve this Mathematics question?

क्योंकि \(x^2\ge 0\), इसलिए \(x^2-9\ge -9\)। परीक्षा में codomain और actual range में फर्क रखें।