यदि (f(x)=x-2+2x) और (g(x)=x-2-2x) हैं, तो \(\frac{f+g}{2}\) कौन सा फलन है?

If (f(x)=x-2+2x) and (g(x)=x-2-2x), which function is \(\frac{f+g}{2}\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2\)

Step 1

Concept

\(f+g=2x^2\), so \(\frac{f+g}{2}=x^2\). Opposite terms cancel when symmetric expressions are added.

Step 2

Why this answer is correct

The correct answer is A. \(x^2\). \(f+g=2x^2\), so \(\frac{f+g}{2}=x^2\). Opposite terms cancel when symmetric expressions are added.

Step 3

Exam Tip

\(f+g=2x^2\), इसलिए \(\frac{f+g}{2}=x^2\)। सममित पद जोड़ने पर विपरीत पद कट जाते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2+2x) और (g(x)=x-2-2x) हैं, तो \(\frac{f+g}{2}\) कौन सा फलन है? / If (f(x)=x-2+2x) and (g(x)=x-2-2x), which function is \(\frac{f+g}{2}\)?

Correct Answer: A. \(x^2\). Explanation: \(f+g=2x^2\), इसलिए \(\frac{f+g}{2}=x^2\)। सममित पद जोड़ने पर विपरीत पद कट जाते हैं। / \(f+g=2x^2\), so \(\frac{f+g}{2}=x^2\). Opposite terms cancel when symmetric expressions are added.

Which concept should I revise for this Mathematics MCQ?

\(f+g=2x^2\), so \(\frac{f+g}{2}=x^2\). Opposite terms cancel when symmetric expressions are added.

What exam hint can help solve this Mathematics question?

\(f+g=2x^2\), इसलिए \(\frac{f+g}{2}=x^2\)। सममित पद जोड़ने पर विपरीत पद कट जाते हैं।