यदि (f(x)=x-2-2x+1) और (g(x)=1-x) हों, तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप क्या है, जहाँ \(x\ne 1\)?
If (f(x)=x-2-2x+1) and (g(x)=1-x), what is the simplified form of (\left\(\frac{f}{g}\right\)(x)), where \(x\ne 1\)?
Explanation opens after your attempt
Correct Answer
A. (1-x)
Concept
(f(x)=(x-1)2) and (g(x)=-(x-1)), so the quotient is (-(x-1)=1-x). Pay special attention to the sign.
Why this answer is correct
The correct answer is A. (1-x). (f(x)=(x-1)2) and (g(x)=-(x-1)), so the quotient is (-(x-1)=1-x). Pay special attention to the sign.
Exam Tip
(f(x)=(x-1)2) और (g(x)=-(x-1)), इसलिए भागफल (-(x-1)=1-x) है। चिह्न पर विशेष ध्यान दें।
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