यदि (f(x)=x-2+2) और (g(x)=x-2+5) हैं, तो \(\frac{f}{g}\) का वास्तविक अधिकतम मान कौन सा है?
If (f(x)=x-2+2) and (g(x)=x-2+5), what is the real maximum value of \(\frac{f}{g}\)?
Explanation opens after your attempt
Correct Answer
C. कोई अधिकतम प्राप्त नहीं होताno maximum is attained
Concept
\(\frac{x^2+2}{x^2+5}=1-\frac{3}{x^2+5}\), so it approaches (1) but never equals (1). Hence no actual maximum is attained.
Why this answer is correct
The correct answer is C. कोई अधिकतम प्राप्त नहीं होता / no maximum is attained. \(\frac{x^2+2}{x^2+5}=1-\frac{3}{x^2+5}\), so it approaches (1) but never equals (1). Hence no actual maximum is attained.
Exam Tip
\(\frac{x^2+2}{x^2+5}=1-\frac{3}{x^2+5}\), इसलिए यह (1) के निकट जाता है पर (1) नहीं बनता। अतः वास्तविक अधिकतम प्राप्त नहीं होता।
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