यदि (f(x)=x-2-12) और वास्तविक डोमेन \(\mathbb{R}\) है, तो रेंज क्या है?
If (f(x)=x-2-12) and the real domain is \(\mathbb{R}\), what is the range?
Explanation opens after your attempt
Correct Answer
A. \([-12,\infty\))
Concept
Since \(x^2\ge0\), \(x^2-12\ge-12\). In exams remember the minimum value of the square function is (0).
Why this answer is correct
The correct answer is A. \([-12,\infty\)). Since \(x^2\ge0\), \(x^2-12\ge-12\). In exams remember the minimum value of the square function is (0).
Exam Tip
क्योंकि \(x^2\ge0\), इसलिए \(x^2-12\ge-12\)। परीक्षा में square function की minimum value (0) याद रखें।
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