यदि (f(x)=x-2-10x+26) और (g(x)=x-2-10x+30) हैं, तो \(\frac{f}{g}\) का न्यूनतम मान क्या है?

If (f(x)=x-2-10x+26) and (g(x)=x-2-10x+30), what is the minimum value of \(\frac{f}{g}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(\frac{1}{5}\)

Explanation

Simple Explanation

(\frac{f}{g}=\frac{(x-5)2+1}{(x-5)2+5}), जो ((x-5)2=0) पर \(\frac{1}{5}\) देता है। समान वर्ग पद को \(t\ge 0\) रखकर देखें। / (\frac{f}{g}=\frac{(x-5)2+1}{(x-5)2+5}), which gives \(\frac{1}{5}\) at ((x-5)2=0). Set the common square term as \(t\ge 0\).

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-10x+26) और (g(x)=x-2-10x+30) हैं, तो \(\frac{f}{g}\) का न्यूनतम मान क्या है? / If (f(x)=x-2-10x+26) and (g(x)=x-2-10x+30), what is the minimum value of \(\frac{f}{g}\)?

Correct Answer: A. \(\frac{1}{5}\). Explanation: (\frac{f}{g}=\frac{(x-5)2+1}{(x-5)2+5}), जो ((x-5)2=0) पर \(\frac{1}{5}\) देता है। समान वर्ग पद को \(t\ge 0\) रखकर देखें। / (\frac{f}{g}=\frac{(x-5)2+1}{(x-5)2+5}), which gives \(\frac{1}{5}\) at ((x-5)2=0). Set the common square term as \(t\ge 0\).