यदि (f(x)=x-2-1) और (g(x)=x+1) हों, तो \(x\ne -1\) के लिए (\left\(\frac{f}{g}\right\)(2)) क्या होगा?
If (f(x)=x-2-1) and (g(x)=x+1), what is (\left\(\frac{f}{g}\right\)(2)) for \(x\ne -1\)?
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Correct Answer
B. (3)
Concept
\(\frac{x^2-1}{x+1}=x-1\), so at (x=2) the value is (1). Directly, (f(2)=3) and (g(2)=3), so the value is (1).
Why this answer is correct
The correct answer is B. (3). \(\frac{x^2-1}{x+1}=x-1\), so at (x=2) the value is (1). Directly, (f(2)=3) and (g(2)=3), so the value is (1).
Exam Tip
\(\frac{x^2-1}{x+1}=x-1\), अतः (x=2) पर मान (1) नहीं बल्कि \(\frac{3}{3}\) से (1) होता है। सही गणना में (f(2)=3) और (g(2)=3), इसलिए मान (1) है।
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