यदि (f(x)=\sqrt{x}) और (g(x)=\sqrt{x}) हैं, तो ((fg)(x)) और उसका प्रांत क्या है?

If (f(x)=\sqrt{x}) and (g(x)=\sqrt{x}), what are ((fg)(x)) and its domain?

Explanation opens after your attempt
Correct Answer

A. \(x, x \geq 0\)

Step 1

Concept

((fg)(x)=\sqrt{x}\cdot\sqrt{x}=x), but both square roots require \(x \geq 0\). The simplified form does not change the original domain.

Step 2

Why this answer is correct

The correct answer is A. \(x, x \geq 0\). ((fg)(x)=\sqrt{x}\cdot\sqrt{x}=x), but both square roots require \(x \geq 0\). The simplified form does not change the original domain.

Step 3

Exam Tip

((fg)(x)=\sqrt{x}\cdot\sqrt{x}=x), लेकिन दोनों वर्गमूलों के लिए \(x \geq 0\)। सरल रूप से प्रांत नहीं बदलता।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x}) और (g(x)=\sqrt{x}) हैं, तो ((fg)(x)) और उसका प्रांत क्या है? / If (f(x)=\sqrt{x}) and (g(x)=\sqrt{x}), what are ((fg)(x)) and its domain?

Correct Answer: A. \(x, x \geq 0\). Explanation: ((fg)(x)=\sqrt{x}\cdot\sqrt{x}=x), लेकिन दोनों वर्गमूलों के लिए \(x \geq 0\)। सरल रूप से प्रांत नहीं बदलता। / ((fg)(x)=\sqrt{x}\cdot\sqrt{x}=x), but both square roots require \(x \geq 0\). The simplified form does not change the original domain.

Which concept should I revise for this Mathematics MCQ?

((fg)(x)=\sqrt{x}\cdot\sqrt{x}=x), but both square roots require \(x \geq 0\). The simplified form does not change the original domain.

What exam hint can help solve this Mathematics question?

((fg)(x)=\sqrt{x}\cdot\sqrt{x}=x), लेकिन दोनों वर्गमूलों के लिए \(x \geq 0\)। सरल रूप से प्रांत नहीं बदलता।