यदि (f(x)=\sqrt{x+3}) और (g(x)=\sqrt{x-1}) हैं, तो \(\frac{f}{g}\) का डोमेन क्या होगा?

If (f(x)=\sqrt{x+3}) and (g(x)=\sqrt{x-1}), what is the domain of \(\frac{f}{g}\)?

Explanation opens after your attempt
Correct Answer

A. ( \(1,\infty\) )

Step 1

Concept

The denominator is (g(x)), so \(\sqrt{x-1}\neq0\) and (x>1) are required. In division, the denominator radical cannot be zero.

Step 2

Why this answer is correct

The correct answer is A. ( \(1,\infty\) ). The denominator is (g(x)), so \(\sqrt{x-1}\neq0\) and (x>1) are required. In division, the denominator radical cannot be zero.

Step 3

Exam Tip

हर (g(x)) है, इसलिए \(\sqrt{x-1}\neq0\) और (x>1) चाहिए। भाग में हर वाले मूल को शून्य नहीं होने देना है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x+3}) और (g(x)=\sqrt{x-1}) हैं, तो \(\frac{f}{g}\) का डोमेन क्या होगा? / If (f(x)=\sqrt{x+3}) and (g(x)=\sqrt{x-1}), what is the domain of \(\frac{f}{g}\)?

Correct Answer: A. ( \(1,\infty\) ). Explanation: हर (g(x)) है, इसलिए \(\sqrt{x-1}\neq0\) और (x>1) चाहिए। भाग में हर वाले मूल को शून्य नहीं होने देना है। / The denominator is (g(x)), so \(\sqrt{x-1}\neq0\) and (x>1) are required. In division, the denominator radical cannot be zero.

Which concept should I revise for this Mathematics MCQ?

The denominator is (g(x)), so \(\sqrt{x-1}\neq0\) and (x>1) are required. In division, the denominator radical cannot be zero.

What exam hint can help solve this Mathematics question?

हर (g(x)) है, इसलिए \(\sqrt{x-1}\neq0\) और (x>1) चाहिए। भाग में हर वाले मूल को शून्य नहीं होने देना है।