यदि (f(x)=\sqrt{x+1}) और (g(x)=\sqrt{x-3}) हों, तो ((f-g)(x)) का डोमेन क्या होगा?

If (f(x)=\sqrt{x+1}) and (g(x)=\sqrt{x-3}), what is the domain of ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. \([3,\infty\))

Step 1

Concept

Both square roots must be defined, so \(x\ge -1\) and \(x\ge 3\). The common domain is \([3,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. \([3,\infty\)). Both square roots must be defined, so \(x\ge -1\) and \(x\ge 3\). The common domain is \([3,\infty\)).

Step 3

Exam Tip

दोनों वर्गमूल परिभाषित होने चाहिए, इसलिए \(x\ge -1\) और \(x\ge 3\)। साझा डोमेन \([3,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x+1}) और (g(x)=\sqrt{x-3}) हों, तो ((f-g)(x)) का डोमेन क्या होगा? / If (f(x)=\sqrt{x+1}) and (g(x)=\sqrt{x-3}), what is the domain of ((f-g)(x))?

Correct Answer: A. \([3,\infty\)). Explanation: दोनों वर्गमूल परिभाषित होने चाहिए, इसलिए \(x\ge -1\) और \(x\ge 3\)। साझा डोमेन \([3,\infty\)) है। / Both square roots must be defined, so \(x\ge -1\) and \(x\ge 3\). The common domain is \([3,\infty\)).

Which concept should I revise for this Mathematics MCQ?

Both square roots must be defined, so \(x\ge -1\) and \(x\ge 3\). The common domain is \([3,\infty\)).

What exam hint can help solve this Mathematics question?

दोनों वर्गमूल परिभाषित होने चाहिए, इसलिए \(x\ge -1\) और \(x\ge 3\)। साझा डोमेन \([3,\infty\)) है।