यदि (f(x)=\sqrt{9-x-2}) और (g(x)=\frac{1}{x}) हैं, तो (fg) का डोमेन क्या होगा?
If (f(x)=\sqrt{9-x-2}) and (g(x)=\frac{1}{x}), what is the domain of (fg)?
Explanation opens after your attempt
Correct Answer
A. ( [-3,3]-{0} )
Concept
For \(\sqrt{9-x^2}\), \(-3\le x\le3\), and for \(\frac{1}{x}\), \(x\neq0\). Hence the domain is ( [-3,3]-{0} ).
Why this answer is correct
The correct answer is A. ( [-3,3]-{0} ). For \(\sqrt{9-x^2}\), \(-3\le x\le3\), and for \(\frac{1}{x}\), \(x\neq0\). Hence the domain is ( [-3,3]-{0} ).
Exam Tip
\(\sqrt{9-x^2}\) के लिए \(-3\le x\le3\) और \(\frac{1}{x}\) के लिए \(x\neq0\) है। अतः डोमेन ( [-3,3]-{0} ) है।
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