यदि (f(x)=\sqrt{4-x}) और (g(x)=\frac{1}{\sqrt{x}}) हों, तो ((fg)(x)) का प्रांत क्या होगा?

If (f(x)=\sqrt{4-x}) and (g(x)=\frac{1}{\sqrt{x}}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. ( (0,4] )

Step 1

Concept

\(\sqrt{4-x}\) needs \(x\le 4\), and \(\sqrt{x}\) in the denominator needs (x>0). The intersection is ( (0,4] ).

Step 2

Why this answer is correct

The correct answer is A. ( (0,4] ). \(\sqrt{4-x}\) needs \(x\le 4\), and \(\sqrt{x}\) in the denominator needs (x>0). The intersection is ( (0,4] ).

Step 3

Exam Tip

\(\sqrt{4-x}\) के लिए \(x\le 4\), और \(\sqrt{x}\) हर में होने से (x>0)। प्रतिच्छेद ( (0,4] ) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{4-x}) और (g(x)=\frac{1}{\sqrt{x}}) हों, तो ((fg)(x)) का प्रांत क्या होगा? / If (f(x)=\sqrt{4-x}) and (g(x)=\frac{1}{\sqrt{x}}), what is the domain of ((fg)(x))?

Correct Answer: A. ( (0,4] ). Explanation: \(\sqrt{4-x}\) के लिए \(x\le 4\), और \(\sqrt{x}\) हर में होने से (x>0)। प्रतिच्छेद ( (0,4] ) है। / \(\sqrt{4-x}\) needs \(x\le 4\), and \(\sqrt{x}\) in the denominator needs (x>0). The intersection is ( (0,4] ).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{4-x}\) needs \(x\le 4\), and \(\sqrt{x}\) in the denominator needs (x>0). The intersection is ( (0,4] ).

What exam hint can help solve this Mathematics question?

\(\sqrt{4-x}\) के लिए \(x\le 4\), और \(\sqrt{x}\) हर में होने से (x>0)। प्रतिच्छेद ( (0,4] ) है।