यदि (f(x)=\sqrt{2x-3}) और (g(x)=\sqrt{7-x}) हों, तो (\left\(\frac{f}{g}\right\)(x)) का प्रांत क्या होगा?

If (f(x)=\sqrt{2x-3}) and (g(x)=\sqrt{7-x}), what is the domain of (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. \( \left[\frac{3}{2},7\right\) )

Step 1

Concept

The numerator root needs \(2x-3\ge 0\), and the denominator root needs (7-x>0). Therefore the domain is \( \left[\frac{3}{2},7\right\) ).

Step 2

Why this answer is correct

The correct answer is A. \( \left[\frac{3}{2},7\right\) ). The numerator root needs \(2x-3\ge 0\), and the denominator root needs (7-x>0). Therefore the domain is \( \left[\frac{3}{2},7\right\) ).

Step 3

Exam Tip

अंश के मूल से \(2x-3\ge 0\) और हर के मूल से (7-x>0) चाहिए। इसलिए प्रांत \( \left[\frac{3}{2},7\right\) ) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{2x-3}) और (g(x)=\sqrt{7-x}) हों, तो (\left\(\frac{f}{g}\right\)(x)) का प्रांत क्या होगा? / If (f(x)=\sqrt{2x-3}) and (g(x)=\sqrt{7-x}), what is the domain of (\left\(\frac{f}{g}\right\)(x))?

Correct Answer: A. \( \left[\frac{3}{2},7\right\) ). Explanation: अंश के मूल से \(2x-3\ge 0\) और हर के मूल से (7-x>0) चाहिए। इसलिए प्रांत \( \left[\frac{3}{2},7\right\) ) है। / The numerator root needs \(2x-3\ge 0\), and the denominator root needs (7-x>0). Therefore the domain is \( \left[\frac{3}{2},7\right\) ).

Which concept should I revise for this Mathematics MCQ?

The numerator root needs \(2x-3\ge 0\), and the denominator root needs (7-x>0). Therefore the domain is \( \left[\frac{3}{2},7\right\) ).

What exam hint can help solve this Mathematics question?

अंश के मूल से \(2x-3\ge 0\) और हर के मूल से (7-x>0) चाहिए। इसलिए प्रांत \( \left[\frac{3}{2},7\right\) ) है।