यदि (f(x)=\frac{x}{x-1}) और (g(x)=\frac{1}{x-1}) हों, तो ((f-g)(x)) का मान क्या होगा?
If (f(x)=\frac{x}{x-1}) and (g(x)=\frac{1}{x-1}), what is ((f-g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(1,\ x\ne 1\)
Concept
\(\frac{x}{x-1}-\frac{1}{x-1}=\frac{x-1}{x-1}=1\), but \(x\ne 1\). The original restriction remains after simplification.
Why this answer is correct
The correct answer is A. \(1,\ x\ne 1\). \(\frac{x}{x-1}-\frac{1}{x-1}=\frac{x-1}{x-1}=1\), but \(x\ne 1\). The original restriction remains after simplification.
Exam Tip
\(\frac{x}{x-1}-\frac{1}{x-1}=\frac{x-1}{x-1}=1\), पर \(x\ne 1\)। सरलीकरण के बाद भी पुराना प्रतिबंध रहता है।
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