समान हर से (f-g=\frac{x-2+1-\(x^2-1\)}{x}=\frac{2}{x}), जहां \(x\ne 0\)। घटाव में दूसरे अंश के दोनों चिन्ह बदलते हैं। / With a common denominator, (f-g=\frac{x-2+1-\(x^2-1\)}{x}=\frac{2}{x}), where \(x\ne 0\). In subtraction, both signs of the second numerator change.
Mathematics Answer, Explanation and Revision Hints
यदि (f(x)=\frac{x-2+1}{x}) और (g(x)=\frac{x-2-1}{x}) हैं, तो ((f-g)(x)) क्या है? / If (f(x)=\frac{x-2+1}{x}) and (g(x)=\frac{x-2-1}{x}), what is ((f-g)(x))?
Correct Answer: A. \(\frac{2}{x}\), \(x\ne 0\). Explanation: समान हर से (f-g=\frac{x-2+1-\(x^2-1\)}{x}=\frac{2}{x}), जहां \(x\ne 0\)। घटाव में दूसरे अंश के दोनों चिन्ह बदलते हैं। / With a common denominator, (f-g=\frac{x-2+1-\(x^2-1\)}{x}=\frac{2}{x}), where \(x\ne 0\). In subtraction, both signs of the second numerator change.
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