यदि (f(x)=\frac{x+1}{x-4}) और (g(x)=x-2) हों, तो ((fg)(x)) का domain क्या है?

If (f(x)=\frac{x+1}{x-4}) and (g(x)=x-2), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{4}\)

Step 1

Concept

The domain of a product is the intersection of both domains, and in (f(x)), \(x\neq 4\). Since (g(x)) is a polynomial, it adds no new restriction.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{4}\). The domain of a product is the intersection of both domains, and in (f(x)), \(x\neq 4\). Since (g(x)) is a polynomial, it adds no new restriction.

Step 3

Exam Tip

product का domain दोनों domains का intersection होता है, और (f(x)) में \(x\neq 4\)। (g(x)) polynomial है, इसलिए कोई नई restriction नहीं है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{x+1}{x-4}) और (g(x)=x-2) हों, तो ((fg)(x)) का domain क्या है? / If (f(x)=\frac{x+1}{x-4}) and (g(x)=x-2), what is the domain of ((fg)(x))?

Correct Answer: A. \(\mathbb{R}-{4}\). Explanation: product का domain दोनों domains का intersection होता है, और (f(x)) में \(x\neq 4\)। (g(x)) polynomial है, इसलिए कोई नई restriction नहीं है। / The domain of a product is the intersection of both domains, and in (f(x)), \(x\neq 4\). Since (g(x)) is a polynomial, it adds no new restriction.

Which concept should I revise for this Mathematics MCQ?

The domain of a product is the intersection of both domains, and in (f(x)), \(x\neq 4\). Since (g(x)) is a polynomial, it adds no new restriction.

What exam hint can help solve this Mathematics question?

product का domain दोनों domains का intersection होता है, और (f(x)) में \(x\neq 4\)। (g(x)) polynomial है, इसलिए कोई नई restriction नहीं है।